Hi Milton,
On 5 Aug 2017, at 03:15, milton mamani <akevalion@gmail.com> wrote:
Hi to all
I want to use the next instruction in my code
response := ZnEasy get: 'https://archive.softwareheritage.org/api/1/origin/git/url/https://github.com...'. response.
The previous code works from command line or in a webbrowser, but I does not work with ZnEasy Because it takes the previous link as: a ZnRequest(GET /api/1/origin/git/url/https:/github.com/hylang/hy)
Could you please tell me what can I do for this situation?
Cheers, Milton
ZnUrl has indeed a problem parsing this URL. It skips empty path segments, we'll have to create an issue for that and we should try to fix it, maintaining current behaviour. The parser is hand written and has evolved a bit over the years, so it is a bit brittle. Seaside's WAUrl seems to have the same problem. It is funny that this only now comes up. Thanks for reporting it. Here is a workaround, by manually creating a ZnUrl object from its elementary components. ZnUrl new scheme: #https; host: 'archive.softwareheritage.org'; addPathSegments: #('api' '1' 'origin' 'git' 'url' 'https:' '' 'github.com' 'hylang' 'hy'); yourself. You can use this as follows. ZnUrl new scheme: #https; host: 'archive.softwareheritage.org'; addPathSegments: #('api' '1' 'origin' 'git' 'url' 'https:' '' 'github.com' 'hylang' 'hy'); retrieveContents. ZnEasy get: (ZnUrl new scheme: #https; host: 'archive.softwareheritage.org'; addPathSegments: #('api' '1' 'origin' 'git' 'url' 'https:' '' 'github.com' 'hylang' 'hy'); yourself). Regards, Sven