July 8, 2015
7:03 p.m.
Sven Van Caekenberghe-2 wrote
where do you find proof for the #withX: meaning 'replace X in a copy of the receiver ' ?
I guess from the collection #with:... messages that start from a fresh copy, but also quickly browsing the image, I see other such uses e.g. #withAngle:, #withNewSelection:, all of which return a new instance with the argument passing through to it independent of the original value. ----- Cheers, Sean -- View this message in context: http://forum.world.st/ZnUrl-withPathSegments-Surprise-tp4836593p4836616.html Sent from the Pharo Smalltalk Developers mailing list archive at Nabble.com.