Dec. 25, 2009
4:43 p.m.
Because the right form of accessing the name of class is:
classOrMetaClass theClassSide name
and right form of testing if behavior is metaclass is
object isBehavior and: [ object isMeta ]
but not:
object name endsWith:'class'
indeed now what do you do if you do not want to have to load a class in memory to manipulate a group of them like a package... you end up doing pseudoClass.... why not but there is nothing that is that dogmatic. Stef