April 24, 2011
8:56 a.m.
Yes Now is there a way that we could make sure that an object is really unregistered? I would write [ann hasSubscriber: anObject] whileTrue: [an unregister: anObject] in the client code but having fullyUnregister: anObject is good to have in special case. Stef
Okay. But i would discourage from using such methods :)
Stef
-- Best regards, Igor Stasenko AKA sig.
-- Best regards, Igor Stasenko AKA sig.