Nov. 23, 2014
4:10 p.m.
More precisely, 365.242199 (http://www.timeanddate.com/date/leapyear.html).
On Nov 22, 2014, at 3:03 AM, Hilaire <hilaire@drgeo.eu> wrote:
I saw some discussion about Duration and year calculus in the list
Given that it is impossible to determine the number of days in a year without the calendar years, should not 365.25 be used in place of 365 to minimize the error ?
So it could look like:
Duration class >> years: aNumber ^ self days: (aNumber * 365.25) truncated seconds: 0
Hilaire
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