Making a bitmap area proportional to a value
Hi, I can arrange elements in a visualization where the size/area of an RTBox is proportional to a specified value, like here: or I can made all avatars (RTBitmaps) appear into this one: But I would like to combine both, making the avatars area proportional to a given value and present them in a RTFlowLayout. Is this possible and how? Thanks, Offray
Hi Offray, this snippet may help... squareResize: aForm to: size | newForm | newForm := Form extent: size @ size depth: aForm depth. (WarpBlt current toForm: newForm) sourceForm: aForm; colorMap: (aForm colormapIfNeededFor: newForm); cellSize: 2; combinationRule: 3; copyQuad: aForm boundingBox innerCorners toRect: newForm boundingBox. ^ newForm of course then you use the Form, and put it into the RT machinery. best regards On Sun, Jul 3, 2016 at 12:21 AM, Offray Vladimir Luna Cárdenas < offray.luna@mutabit.com> wrote:
Hi,
I can arrange elements in a visualization where the size/area of an RTBox is proportional to a specified value, like here:
or I can made all avatars (RTBitmaps) appear into this one:
But I would like to combine both, making the avatars area proportional to a given value and present them in a RTFlowLayout. Is this possible and how?
Thanks,
Offray
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Hi Offray! Just to make clear I am understanding correctly, you want to scale a bitmap, based on a given metric. Is that right? Alexandre
On Jul 3, 2016, at 5:21 AM, Offray Vladimir Luna Cárdenas <offray.luna@mutabit.com> wrote:
Hi,
I can arrange elements in a visualization where the size/area of an RTBox is proportional to a specified value, like here:
<ciminpknloldbifd.png>
or I can made all avatars (RTBitmaps) appear into this one:
<aehbdmimebjfkdai.png>
But I would like to combine both, making the avatars area proportional to a given value and present them in a RTFlowLayout. Is this possible and how?
Thanks,
Offray
_______________________________________________ Moose-dev mailing list Moose-dev@list.inf.unibe.ch https://www.list.inf.unibe.ch/listinfo/moose-dev
-- _,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;: Alexandre Bergel http://www.bergel.eu ^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;._,.;:~^~:;.
participants (3)
-
Alexandre Bergel -
Arturo Zambrano -
Offray Vladimir Luna Cárdenas