ZipFileMember>>contentStream has leading characters
Hi everybody! This is my first post and I'm posting this question after going around this forum without finding answer for my question. I couldn't wrap my mind around it. Here is the issue (in fact it is not a issue, classes work fine). I want to uncompress a zip file and file in the content of one of the file included in zip file. For instance: The file 'tp1.zip' contains just one file inside it: 'test.st'. Once I uncompressed it, using code bellow: I found that file stream has a set of leading characters which cannot be interpreted by *CodeInterpreter*. Here you will fine these leading characters: /Hexa characters/ *ef bb bf * /Ascii characters/ *ef bb bf * Indeed, this leading characters are written by the fileOut process and it's ok (those are magic number which depend on the SO) but I don't know how to skip it for CodeInterpreter to be able fileIn this file. My first solution was skipping this characters through the use of /Stream>>next: 4/. But I'm looking for a much portable solution. Somebody went through this problem? Thanks for help in advance. DiegoS -- View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com.
What is the code that you use? Doru On Mon, Oct 13, 2014 at 1:31 AM, DiegoSanchez <diego.sanches@gmail.com> wrote:
Hi everybody! This is my first post and I'm posting this question after going around this forum without finding answer for my question. I couldn't wrap my mind around it.
Here is the issue (in fact it is not a issue, classes work fine).
I want to uncompress a zip file and file in the content of one of the file included in zip file. For instance: The file 'tp1.zip' contains just one file inside it: 'test.st'.
Once I uncompressed it, using code bellow:
I found that file stream has a set of leading characters which cannot be interpreted by *CodeInterpreter*.
Here you will fine these leading characters:
/Hexa characters/ *ef bb bf *
/Ascii characters/ *ef bb bf *
Indeed, this leading characters are written by the fileOut process and it's ok (those are magic number which depend on the SO) but I don't know how to skip it for CodeInterpreter to be able fileIn this file.
My first solution was skipping this characters through the use of /Stream>>next: 4/. But I'm looking for a much portable solution.
Somebody went through this problem?
Thanks for help in advance. DiegoS
-- View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com.
-- www.tudorgirba.com "Every thing has its own flow"
doitFromStream | zipper file | zipper := ZipArchive new readFrom: '/Users/diego/tp1-95195.zip'. file := zipper members at: 2. "file contentStream returns the stream with file's information uncompressed" On 13 October 2014 08:15, Tudor Girba <tudor@tudorgirba.com> wrote:
What is the code that you use?
Doru
On Mon, Oct 13, 2014 at 1:31 AM, DiegoSanchez <diego.sanches@gmail.com> wrote:
Hi everybody! This is my first post and I'm posting this question after going around this forum without finding answer for my question. I couldn't wrap my mind around it.
Here is the issue (in fact it is not a issue, classes work fine).
I want to uncompress a zip file and file in the content of one of the file included in zip file. For instance: The file 'tp1.zip' contains just one file inside it: 'test.st'.
Once I uncompressed it, using code bellow:
I found that file stream has a set of leading characters which cannot be interpreted by *CodeInterpreter*.
Here you will fine these leading characters:
/Hexa characters/ *ef bb bf *
/Ascii characters/ *ef bb bf *
Indeed, this leading characters are written by the fileOut process and it's ok (those are magic number which depend on the SO) but I don't know how to skip it for CodeInterpreter to be able fileIn this file.
My first solution was skipping this characters through the use of /Stream>>next: 4/. But I'm looking for a much portable solution.
Somebody went through this problem?
Thanks for help in advance. DiegoS
-- View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com.
-- www.tudorgirba.com
"Every thing has its own flow"
-- Saludos DiegoS ------ Diego Sanchez [image: http://]about.me/sanchez.diego <http://about.me/sanchez.diego?promo=email_sig>
| zipper file | zipper := ZipArchive new readFrom: 'tp1.zip'. "file contains test.st" file := zipper members at: 1. "file contentStream returns the stream with file's information uncompressed" On 13 October 2014 08:22, Diego Sánchez <diego.sanches@gmail.com> wrote:
doitFromStream | zipper file | zipper := ZipArchive new readFrom: '/Users/diego/tp1-95195.zip'. file := zipper members at: 2.
"file contentStream returns the stream with file's information uncompressed"
On 13 October 2014 08:15, Tudor Girba <tudor@tudorgirba.com> wrote:
What is the code that you use?
Doru
On Mon, Oct 13, 2014 at 1:31 AM, DiegoSanchez <diego.sanches@gmail.com> wrote:
Hi everybody! This is my first post and I'm posting this question after going around this forum without finding answer for my question. I couldn't wrap my mind around it.
Here is the issue (in fact it is not a issue, classes work fine).
I want to uncompress a zip file and file in the content of one of the file included in zip file. For instance: The file 'tp1.zip' contains just one file inside it: 'test.st'.
Once I uncompressed it, using code bellow:
I found that file stream has a set of leading characters which cannot be interpreted by *CodeInterpreter*.
Here you will fine these leading characters:
/Hexa characters/ *ef bb bf *
/Ascii characters/ *ef bb bf *
Indeed, this leading characters are written by the fileOut process and it's ok (those are magic number which depend on the SO) but I don't know how to skip it for CodeInterpreter to be able fileIn this file.
My first solution was skipping this characters through the use of /Stream>>next: 4/. But I'm looking for a much portable solution.
Somebody went through this problem?
Thanks for help in advance. DiegoS
-- View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com.
-- www.tudorgirba.com
"Every thing has its own flow"
-- Saludos DiegoS
------
Diego Sanchez [image: http://]about.me/sanchez.diego <http://about.me/sanchez.diego?promo=email_sig>
-- Saludos DiegoS ------ Diego Sanchez [image: http://]about.me/sanchez.diego <http://about.me/sanchez.diego?promo=email_sig>
You are likely referring to the issue reported here: https://pharo.fogbugz.com/f/cases/12826/Zip-FileSystem-does-not-work This should work now in the latest Pharo 4.0. If you are using Pharo 3.0, loading the slice manually from the Pharo40Inbox should fix the issue as well. What version are you using? Cheers, Doru On Mon, Oct 13, 2014 at 1:23 PM, Diego Sánchez <diego.sanches@gmail.com> wrote:
| zipper file | zipper := ZipArchive new readFrom: 'tp1.zip'.
"file contains test.st" file := zipper members at: 1.
"file contentStream returns the stream with file's information uncompressed"
On 13 October 2014 08:22, Diego Sánchez <diego.sanches@gmail.com> wrote:
doitFromStream | zipper file | zipper := ZipArchive new readFrom: '/Users/diego/tp1-95195.zip'. file := zipper members at: 2.
"file contentStream returns the stream with file's information uncompressed"
On 13 October 2014 08:15, Tudor Girba <tudor@tudorgirba.com> wrote:
What is the code that you use?
Doru
On Mon, Oct 13, 2014 at 1:31 AM, DiegoSanchez <diego.sanches@gmail.com> wrote:
Hi everybody! This is my first post and I'm posting this question after going around this forum without finding answer for my question. I couldn't wrap my mind around it.
Here is the issue (in fact it is not a issue, classes work fine).
I want to uncompress a zip file and file in the content of one of the file included in zip file. For instance: The file 'tp1.zip' contains just one file inside it: 'test.st'.
Once I uncompressed it, using code bellow:
I found that file stream has a set of leading characters which cannot be interpreted by *CodeInterpreter*.
Here you will fine these leading characters:
/Hexa characters/ *ef bb bf *
/Ascii characters/ *ef bb bf *
Indeed, this leading characters are written by the fileOut process and it's ok (those are magic number which depend on the SO) but I don't know how to skip it for CodeInterpreter to be able fileIn this file.
My first solution was skipping this characters through the use of /Stream>>next: 4/. But I'm looking for a much portable solution.
Somebody went through this problem?
Thanks for help in advance. DiegoS
-- View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com.
-- www.tudorgirba.com
"Every thing has its own flow"
-- Saludos DiegoS
------
Diego Sanchez [image: http://]about.me/sanchez.diego <http://about.me/sanchez.diego?promo=email_sig>
-- Saludos DiegoS
------
Diego Sanchez [image: http://]about.me/sanchez.diego <http://about.me/sanchez.diego?promo=email_sig>
-- www.tudorgirba.com "Every thing has its own flow"
Thanks Tudor, Yes I'm using Pharo 3. On 13 October 2014 08:33, Tudor Girba-2 [via Smalltalk] < ml-node+s1294792n4784295h3@n4.nabble.com> wrote:
You are likely referring to the issue reported here: https://pharo.fogbugz.com/f/cases/12826/Zip-FileSystem-does-not-work
This should work now in the latest Pharo 4.0. If you are using Pharo 3.0, loading the slice manually from the Pharo40Inbox should fix the issue as well.
What version are you using?
Cheers, Doru
On Mon, Oct 13, 2014 at 1:23 PM, Diego Sánchez <[hidden email] <http://user/SendEmail.jtp?type=node&node=4784295&i=0>> wrote:
| zipper file | zipper := ZipArchive new readFrom: 'tp1.zip'.
"file contains test.st" file := zipper members at: 1.
"file contentStream returns the stream with file's information uncompressed"
On 13 October 2014 08:22, Diego Sánchez <[hidden email] <http://user/SendEmail.jtp?type=node&node=4784295&i=1>> wrote:
doitFromStream | zipper file | zipper := ZipArchive new readFrom: '/Users/diego/tp1-95195.zip'. file := zipper members at: 2.
"file contentStream returns the stream with file's information uncompressed"
On 13 October 2014 08:15, Tudor Girba <[hidden email] <http://user/SendEmail.jtp?type=node&node=4784295&i=2>> wrote:
What is the code that you use?
Doru
On Mon, Oct 13, 2014 at 1:31 AM, DiegoSanchez <[hidden email] <http://user/SendEmail.jtp?type=node&node=4784295&i=3>> wrote:
Hi everybody! This is my first post and I'm posting this question after going around this forum without finding answer for my question. I couldn't wrap my mind around it.
Here is the issue (in fact it is not a issue, classes work fine).
I want to uncompress a zip file and file in the content of one of the file included in zip file. For instance: The file 'tp1.zip' contains just one file inside it: 'test.st'.
Once I uncompressed it, using code bellow:
I found that file stream has a set of leading characters which cannot be interpreted by *CodeInterpreter*.
Here you will fine these leading characters:
/Hexa characters/ *ef bb bf *
/Ascii characters/ *ef bb bf *
Indeed, this leading characters are written by the fileOut process and it's ok (those are magic number which depend on the SO) but I don't know how to skip it for CodeInterpreter to be able fileIn this file.
My first solution was skipping this characters through the use of /Stream>>next: 4/. But I'm looking for a much portable solution.
Somebody went through this problem?
Thanks for help in advance. DiegoS
-- View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com.
-- www.tudorgirba.com
"Every thing has its own flow"
-- Saludos DiegoS
------
Diego Sanchez [image: http://]about.me/sanchez.diego <http://about.me/sanchez.diego?promo=email_sig>
-- Saludos DiegoS
------
Diego Sanchez [image: http://]about.me/sanchez.diego <http://about.me/sanchez.diego?promo=email_sig>
-- www.tudorgirba.com
"Every thing has its own flow"
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-- Saludos DiegoS ------ Diego Sanchez [image: http://]about.me/sanchez.diego <http://about.me/sanchez.diego?promo=email_sig> -- View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com.
On 13/10/14 01:31, DiegoSanchez wrote:
Hi everybody! This is my first post
Welcome :) In which image version are you?
and I'm posting this question after going around this forum without finding answer for my question. I couldn't wrap my mind around it.
Here is the issue (in fact it is not a issue, classes work fine).
I want to uncompress a zip file and file in the content of one of the file included in zip file. For instance: The file 'tp1.zip' contains just one file inside it: 'test.st'.
Once I uncompressed it, using code bellow:
I found that file stream has a set of leading characters which cannot be interpreted by *CodeInterpreter*.
Here you will fine these leading characters:
/Hexa characters/ *ef bb bf *
/Ascii characters/ *ef bb bf *
Indeed, this leading characters are written by the fileOut process and it's ok (those are magic number which depend on the SO) but I don't know how to skip it for CodeInterpreter to be able fileIn this file.
My first solution was skipping this characters through the use of /Stream>>next: 4/. But I'm looking for a much portable solution.
Somebody went through this problem?
Thanks for help in advance. DiegoS
-- View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com.
I'm using Pharo 3.0 image ( http://files.pharo.org/image/30/Pharo-Image-3.0-latest.zip) On 14 October 2014 03:25, stepharo [via Smalltalk] < ml-node+s1294792n4784442h60@n4.nabble.com> wrote:
On 13/10/14 01:31, DiegoSanchez wrote:
Hi everybody! This is my first post
Welcome :) In which image version are you?
and I'm posting this question after going around this forum without finding answer for my question. I couldn't wrap my mind around it.
Here is the issue (in fact it is not a issue, classes work fine).
I want to uncompress a zip file and file in the content of one of the file included in zip file. For instance: The file 'tp1.zip' contains just one file inside it: 'test.st'.
Once I uncompressed it, using code bellow:
I found that file stream has a set of leading characters which cannot be interpreted by *CodeInterpreter*.
Here you will fine these leading characters:
/Hexa characters/ *ef bb bf *
/Ascii characters/ *ef bb bf *
Indeed, this leading characters are written by the fileOut process and it's ok (those are magic number which depend on the SO) but I don't know how to skip it for CodeInterpreter to be able fileIn this file.
My first solution was skipping this characters through the use of /Stream>>next: 4/. But I'm looking for a much portable solution.
Somebody went through this problem?
Thanks for help in advance. DiegoS
-- View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com.
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-- Saludos DiegoS ------ Diego Sanchez [image: http://]about.me/sanchez.diego <http://about.me/sanchez.diego?promo=email_sig> -- View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com.
DiegoSanchez wrote:
I'm using Pharo 3.0 image (http://files.pharo.org/image/30/Pharo-Image-3.0-latest.zip)
That link changes from day to day. Can you report... World Menu > System > System Reporter > Image > Latest update. -ben
On 14 October 2014 03:25, stepharo [via Smalltalk] <[hidden email] </user/SendEmail.jtp?type=node&node=4784515&i=0>> wrote:
On 13/10/14 01:31, DiegoSanchez wrote: > Hi everybody! This is my first post
Welcome :) In which image version are you?
> and I'm posting this question after > going around this forum without finding answer for my question. I couldn't > wrap my mind around it. > > Here is the issue (in fact it is not a issue, classes work fine). > > I want to uncompress a zip file and file in the content of one of the file > included in zip file. For instance: > The file 'tp1.zip' contains just one file inside it: 'test.st <http://test.st>'. > > Once I uncompressed it, using code bellow: > > > > I found that file stream has a set of leading characters which cannot be > interpreted by *CodeInterpreter*. > > Here you will fine these leading characters: > > /Hexa characters/ > *ef bb bf * > > /Ascii characters/ > *ef bb bf * > > Indeed, this leading characters are written by the fileOut process and it's > ok (those are magic number which depend on the SO) but I don't know how to > skip it for CodeInterpreter to be able fileIn this file. > > My first solution was skipping this characters through the use of > /Stream>>next: 4/. But I'm looking for a much portable solution. > > Somebody went through this problem? > > Thanks for help in advance. > DiegoS > > > > -- > View this message in context: http://forum.world.st/ZipFileMember-contentStream-has-leading-characters-tp4... > Sent from the Pharo Smalltalk Users mailing list archive at Nabble.com. > >
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-- Saludos DiegoS
------
Diego Sanchez http://about.me/sanchez.diego
<http://about.me/sanchez.diego?promo=email_sig>
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participants (5)
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Ben Coman -
Diego Sánchez -
DiegoSanchez
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stepharo -
Tudor Girba