Thank you Guillermo. I see that you already assigned the case https://pharo.fogbugz.com/f/cases/20253/MemoryFileSysteFile-shuold-return-a-MultiByteFileStream-as-readStream 

Cheers,
Juraj

On Nov 30, 2017, at 06:10, Guillermo Polito <guillermopolito@gmail.com> wrote:

Hi Juraj,

The file streams opened in a memory file system are not polymorphic with the ones in a disk file system :(.

Can you open an issue and assing it to me? I'll work soon on making all of them work and yield binary streams.

On Wed, Nov 29, 2017 at 9:06 PM, Juraj Kubelka <juraj.kubelka@icloud.com> wrote:
Hi,

I can successfully use ZipArchive like the following

-=-=-
zip := ZipArchive new.
{ 'file1.txt'. 'file2.txt'. 'file3.txt' } do: [ :eachFile |
        | member |
        member := zip addString: eachFile, ' contents' as: eachFile.
        member desiredCompressionMethod: ZipArchive compressionDeflated ].
file := FileLocator temp / 'archive.zip'.
zip writeTo: file writeStream.
file.
-=-=-

What I should do to make it work while using FileSystem memory?

-=-=-
zip := ZipArchive new.
{ 'file1.txt'. 'file2.txt'. 'file3.txt' } do: [ :eachFile |
        | member |
        member := zip addString: eachFile, ' contents' as: eachFile.
        member desiredCompressionMethod: ZipArchive compressionDeflated ].
fileSystem := FileSystem memory.
file := fileSystem root / 'archive.zip'.
file writeStreamDo: [ :stream |
        zip writeTo: stream ].
-=-=-

There is "Improper store into indexable object��� as it tries to store a number in ByteString.
Thanks!
Juraj





--
   
Guille Polito
Research Engineer


Centre de Recherche en Informatique, Signal et Automatique de Lille
CRIStAL - UMR 9189
French National Center for Scientific Research - http://www.cnrs.fr

Phone: +33 06 52 70 66 13