Hi Damien,On 15 May 2017 at 15:26, Eliot Miranda <eliot.miranda@gmail.com> wrote:Try something like�� �� �� �� shellCommand: 'bash -c ''ls ~''';But then that would run ls inside of bash inside of the system shell (/bin/sh), wouldn't it? What's the point?-c's argument is parsed by the shell so one gets full expansion.�� Further, if there are arguments after the string, they are assigned to the positional parameters, so that�� �� sh -c 'echo ~/$0' foo��prints /Users/eliot/fooThat may be useful.