Hi,

�� have you try with ��(World>>Help>>Help Browser>>Regular Expressions Framework>>Usage)

SUBEXPRESSION MATCHES

After a successful match attempt, you can query the specifics of which
part of the original string has matched which part of the whole
expression.

A subexpression is a parenthesized part of a regular expression, or
the whole expression. When a regular expression is compiled, its
subexpressions are assigned indices starting from 1, depth-first,
left-to-right. For example, `((ab)+(c|d))?ef' includes the following
subexpressions with these indices:

1: ((ab)+(c|d))?ef
2: (ab)+(c|d)
3: ab
4: c|d

After a successful match, the matcher can report what part of the
original string matched what subexpression.


And theres an example��

This facility provides a convenient way of extracting parts of input
strings of complex format. For example, the following piece of code
uses the 'MMM DD, YYYY' date format recognizer example from the
`Syntax' section to convert a date to a three-element array with year,
month, and day strings (you can select and evaluate it right here):

| matcher |
matcher := RxMatcher forString: '(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)[ ]+(:isDigit::isDigit:?)[ ]*,[ ]*(19|20)(:isDigit::isDigit:)'.
(matcher matches: 'Aug 6, 1996')
ifTrue:��
[Array��
with: (matcher subexpression: 5)
with: (matcher subexpression: 2)
with: (matcher subexpression: 3)]
ifFalse: ['no match']

(should answer ` #('96' 'Aug' '6')').


you could make two subexpressions��

��'([\s.;\:!?]*)(#\w+)'

first subexpression is��([\s.;\:!?]*)��
and second subexpression is��(#\w+)��

and then use��

It understandards these
messages:

subexpressionCount

Answers the total number of subexpressions: the highest value that
can be used as a subexpression index with this matcher. This value
is available immediately after initialization and never changes.

subexpression: anIndex

An index must be a valid subexpression index, and this message
must be sent only after a successful match attempt. The method
answers a substring of the original string the corresponding
subexpression has matched to.






On Mon, Aug 8, 2016 at 7:10 PM, Casimiro - GMAIL <casimiro.barreto@gmail.com> wrote:
If someone�� can help me... I'm dealing with the following situation:


�� �� I may have a string in which matches of the following regex:
'[\s.;\:!?]*#\w+' may happen (multiple times). I want to replace the
#\w+ part of it by nothing but keep the [\s.;\:!?]* but it seems to be
no easy way using copyWithRegex: matchesTranslatedWith: or
copyWithRegex: matchesReplacedWith:

Someone knows an easy (meaning, no several operations, etc) to do this????


Thanks in advance,


Casimiro Barreto


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