* Points are summable�� " { 2@2 . 3@3 } " --> 5@5.�� ��But then�� " 2@2 +
1 " --> 3@3�� ��,�� ��so�� " {} sum "�� returning�� 0�� would seem to not
cause any error in this case.
cheers -ben
but points aren't commutative:
2@2 + 1 " = 3@3"
1 + 2@2 " = 3@2"
Of course, 0 wouldn't be an issue, unless you wanted to access x or y!