Yes
Now is there a way that we could make sure that an object is really unregistered?
I would write
� � � �[ann hasSubscriber: anObject] whileTrue: [an unregister: anObject]
in the client code
but having
fullyUnregister: anObject
is good to have in special case.
Stef
> Okay. But i would discourage from using such methods :)
>
>> Stef
>>
>>>
>>>
>>> --
>>> Best regards,
>>> Igor Stasenko AKA sig.
>>>
>>
>>
>>
>
>
>
> --
> Best regards,
> Igor Stasenko AKA sig.
>